24x^2-70x+50=0

Solution for 24x^2-70x+50=0 equation:

24x^2-70x+50=0

a = 24; b = -70; c = +50;
Δ = b2-4ac
Δ = -702-4·24·50
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-10}{2*24}=\frac{60}{48}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+10}{2*24}=\frac{80}{48}
=1+2/3
$